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Section 3.2 Addition and Subtraction Formulas

In Section 1.4, we used right triangles to determine the deviation of a waʻa (canoe) from its course based on the angle of deviation. If a waʻa sails for 120 nautical miles (NM), we were able to calculate the deviation from its course using right triangles to get the equation:
deviation=(120 NM)sin(θ).
Before setting sail, a voyager studies a table listing the deviation distances corresponding to different houses of deviation. It’s crucial to understand that while adding angles may yield a third angle, adding their corresponding deviations will not accurately determine the total deviation. In other words:
sin(α)+sin(β)sin(α+β)
for some angles of deviation α and β.
To illustrate this, let’s calculate the deviation distances for 1, 2, and 3 houses respectively. Using the given formula, we have:
120sin(1 house)=120sin(11.25)23.4 NM120sin(2 houses)=120sin(22.5)45.9 NM120sin(3 houses)=120sin(33.75)66.7 NM
However,
120sin(1 house)+120sin(2 houses)23.4+45.9 NM69.3 NM,
which differs from the actual deviation of 66.7 NM when deviating by 3 houses.
hese calculations demonstrate that the deviation distances for multiple houses cannot be determined by simply adding individual deviations, highlighting the importance of understanding trigonometric principles for accurate navigation. In this section, we will explore formulas for the addition and subtraction of angles in trigonometric functions.

Subsection 3.2.1 Addition and Subtraction Formulas for Cosine

First we will derive the addition and subtraction formulas for the cosine function.

Definition 3.2.1. Addition and Subtraction Formulas for Cosine.

cos(α+β)=cosαcosβsinαsinβcos(αβ)=cosαcosβ+sinαsinβ

Proof.

First we will prove the Subtraction Formula for Cosine
cos(αβ)=cosαcosβ+sinαsinβ.
We begin by considering two points on the unit circle. Point P is at an angle of β in standard position with coordinates (cosβ,sinβ) and point Q is at an angle of α in standard position with coordinates (cosα,sinα).
We use the Distance Formula to calculate the distance between P and Q to get
d(P,Q)=(cosαcosβ)2+(sinαsinβ)2=cos2α2cosαcosβ+cos2β+sin2α2sinαsinβ+sin2β=(cos2α+sin2α)+(cos2β+sin2β)2cosαcosβ2sinαsinβ
Then by the Pythagorean Identity (Definition 1.5.20), cos2α+sin2α=1 and cos2β+sin2β=1. Thus the distance becomes
d(P,Q)=1+12cosαcosβ2sinαsinβ=22cosαcosβ2sinαsinβ
Next, consider two additional points on a second unit circle. Point A has coordinates at (1,0) and Point B is at an angle of αβ in standard position with coordinates (cos(αβ),sin(αβ)).
The distance between A and B is
d(A,B)=(cos(αβ)1)2+(sin(αβ)0)2=cos2(αβ)2cos(αβ)+1+sin2(αβ)=(cos2(αβ)+sin2(αβ))2cos(αβ)+1=12cos(αβ)+1=22cos(αβ)
Note that since OP, OQ, OA, and OB are lines from the center to points on the unit circle, they are congruent and have length of 1. Also note that POB=AOB=αβ. Then since two sides and the included angle of ΔOPQ and ΔOAB are equivalent, we can conclude by the Side-Angle-Side Theorem (SAS) in geometry that the two triangles are congruent. Thus, corresponding sides have the same lengths, giving us: d(PQ)=d(AB). Substituting our results for d(P,Q) and d(A,B) we get
d(PQ)=d(AB)22cosαcosβ2sinαsinβ=22cos(αβ)22cosαcosβ2sinαsinβ=22cos(αβ)2cosαcosβ2sinαsinβ=2cos(αβ)
Dividing both sides by -2 we arrive at the Subtraction Formula for Cosine
cosαcosβ+sinαsinβ=cos(αβ)
To prove the Addition Formula for Cosine, replace β with β in the Subtraction Formula and use the Even and Odd Trigonometric Properties (Definition 1.5.22) where sin(β)=sinβ and cos(β)=cosβ to get
cosαcos(β)+sinαsin(β)=cos(α(β))cosαcos(β)+sinα(sinβ)=cos(α+β)cosαcosβsinαsinβ=cos(α+β)

Example 3.2.2.

Find the exact value of cos105.

Solution.

First note that 105=60+45. Now, using the Addition Formula for Cosine (Definition 3.2.1),
cos105=cos(60+45)=cos60cos45sin60sin45=12223222=14(26)

Example 3.2.3.

Find the exact value of cos(π4π6).

Solution.

Using the Subtraction Formula for Cosine we get
cos(π4π6)=cosπ4cosπ6+sinπ4sinπ6=2232+2212=14(6+2)

Example 3.2.4.

Find the exact value of the expression cos25cos35sin25sin35.

Solution.

Notice this expression is the Addition Formula for Cosine with α=25 and β=35. So
cos25cos35sin25sin35=cos(25+35)=cos60=12

Subsection 3.2.2 Addition and Subtraction Formulas for Sine

Next we will learn about the addition and subtraction formulas for the sine function.

Definition 3.2.5. Addition and Subtraction Formulas for Sine.

sin(α+β)=sinαcosβ+cosαsinβsin(αβ)=sinαcosβcosαsinβ
We will prove the Addition Formula for Sine in Example 3.2.10 and the Subtraction Formula can be established using the Even and Odd Properties (Definition 1.5.22).

Example 3.2.6.

Given sinα=1213, with 3π2<α<2π and cosβ=35, with π2<β<π, find the exact value of sin(α+β).

Solution.

The Addition Formula for Sine gives us
sin(α+β)=sinαcosβ+cosαsinβ
At this moment, we do not know the exact values of cosα and sinβ but we can compute them.
Given sinα=1213 with 3π2<α<2π and cosβ=35 with π2<β<π, we can draw the following triangles associated with α and β, respectively:
Next, using the Pythagorean Theorem, we solve for the missing sides on the triangles
x2+(12)2=132x+144=169x2=25x=5
Thus we get
cosα=513
(3)2+y2=529+y2=25y2=16y=4
Thus we get
sinβ=45
We now have all the information needed to proceed.
sin(α+β)=sinαcosβ+cosαsinβ=(1213)(35)+(513)(45)=3665+2065=5665
Notice we did not have to know the values of α or β to do this example.

Subsection 3.2.3 Addition and Subtraction Formulas for Tangent

Now we will learn about the addition and subtraction formulas for the tangent function.

Definition 3.2.7. Addition and Subtraction Formulas for Tangent.

tan(α+β)=tanα+tanβ1tanαtanβtan(αβ)=tanαtanβ1+tanαtanβ

Proof.

Recall that tanθ=sinθcosθ as long as cosθ0. Using this fact, and our new formulas for the sum of sine and cosine, we get
tan(α+β)=sin(α+β)cos(α+β)=sinαcosβ+cosαsinβcosαcosβsinαsinβ=sinαcosβ+cosαsinβcosαcosβcosαcosβsinαsinβcosαcosβ=sinαcosβcosαcosβ+cosαsinβcosαcosβcosαcosβcosαcosβsinαsinβcosαcosβ=sinαcosα+sinβcosβ1sinαcosαsinβcosβ=tanα+tanβ1tanαtanβ
The subtraction formula can be established using the Even and Odd Properties (Definition 1.5.22).

Example 3.2.8.

Find the exact value of tan(3π4+π6)

Solution.

Using the Addition Formula for Tangent (Definition 3.2.7), we get
tan(3π4+π6)=tan3π4+tanπ61tan3π4tanπ6=(1)+331(1)33=1+331+33=3+333+33=3+33+3

Subsection 3.2.4 Cofunction Identities

Recall the Cofunction Identities (Definition 1.4.7):
sinθ=cos(π2θ),cosθ=sin(π2θ)tanθ=cot(π2θ),cotθ=tan(π2θ)secθ=csc(π2θ),cscθ=sec(π2θ)
Armed with the knowledge of the subtraction formulas, we can prove the Cofunction Identities.

Example 3.2.9.

Use the Subtraction Formula for Sine to establish the identity cosθ=sin(π2θ).

Solution.

To establish an identity, we will start from one side of the equality and use properties to end up with the expression on the other side of the equality. So,
sin(π2θ)=sin(π2)cos(θ)cos(π2)sin(θ)=1cos(θ)0sin(θ)=cos(θ)
Visually, we have cosθ=xr=sin(π2θ):

Example 3.2.10.

Prove the Addition Formula for Sine
sin(α+β)=sinαcosβ+cosαsinβ

Solution.

We begin by using the cofunction identity
sin(α+β)=cos(π2(α+β))=cos((π2α)β)
By the Subtraction Formula for Cosine:
=cos(π2α)cosβ+sin(π2α)sinβ=sinαcosβ+cosαsinβ
where the last step we use the Cofunction Identity.

Subsection 3.2.5 Sums of Sines and Cosines

Sometimes we may come across functions of the form
asinx+bcosx
It can often be useful to rewrite this expression as a single trigonomteric function.

Definition 3.2.11.

For any real numbers a and b, let θ be an angle in standard position where P(a,b) is a point on the terminal side of θ. Then
asinx+bcosx=a2+b2sin(x+θ).

Proof.

We begin by considering the triangle formed by the angle θ and point P(a,b), shown in Figure 3.2.12. By the Pythagorean Theorem, the hypotenuse of this triangle, with base a and height b, is a2+b2. According to Definition 1.4.1, we have:
cosθ=aa2+b2,sinθ=ba2+b2
or equivalently:
a=a2+b2cosθ,b=a2+b2sinθ
Figure 3.2.12. A triangle is formed by angle θ and point P(a,b).
Therefore, using the addition formula for sine, we get
asinx+bcosx=a2+b2cosθsinx+a2+b2sinθcosx=a2+b2(cosθsinx+sinθcosx)=a2+b2sin(x+θ)

Example 3.2.13.

Express
32sinx+12cosx
in terms of sine only.

Solution.

To express the given expression in terms of sine only, we will use Definition 3.2.11. Considering the point P(a,b)=(32,12), which lies in Quadrant II, we determine the angle θ. Using either Table 1.5.18 or inverse trigonometric methods where
tanθ=ba,
we find
θ=150.
Therefore, by Definition 3.2.11, we have:
32sinx+12cosx=(32)2+(12)2sin(x+150)=34+14sin(x+150)=sin(x+150)

Subsection 3.2.6 Summary

To review, the addition and subtraction formulas are
sin(α+β)=sinαcosβ+cosαsinβsin(αβ)=sinαcosβcosαsinβcos(α+β)=cosαcosβsinαsinβcos(αβ)=cosαcosβ+sinαsinβtan(α+β)=tanα+tanβ1tanαtanβtan(αβ)=tanαtanβ1+tanαtanβ

Exercises 3.2.7 Exercises

Exercise Group.

Use the Addition or Subtraction Formula to find the exact value of each expression.

Exercise Group.

Use the Addition or Subtraction Formula to find the exact value of each expression.
13.
sin(172)cos(68)+cos(172)sin(68)
Answer.
32
14.
sin(317)cos(257)cos(317)sin(257)
15.
cos(337)cos(22)+sin(337)sin(22)
Answer.
12
16.
cos(59)cos(211)sin(59)sin(211)
17.
tan(85)tan(25)1+tan(85)tan(25)
18.
sin(5π16)cos(π16)cos(5π16)sin(π16)
19.
cos(5π22)cos(3π11)sin(5π22)sin(3π11)
20.
tan(π7)+tan(4π21)1tan(π7)tan(4π21)

Exercise Group.

Find the exact value of each expression given
27.
sin(α+β)
Answer.
352129+452029=143145
28.
cos(α+β)
Answer.
452129352029=24145
29.
tan(α+β)
Answer.
34+20211342021=14324
30.
sin(αβ)
Answer.
352129452029=17145
31.
cos(αβ)
Answer.
452129+352029=144145
32.
tan(αβ)
Answer.
3420211+342021=1724

Exercise Group.

Find the exact value of each expression given
39.
sin(α+β)
Answer.
15521313+10531313=2195+313065
41.
tan(α+β)
Answer.
62+3216232=3013619
42.
sin(αβ)
Answer.
1052131315531313=2130319565
43.
cos(αβ)
Answer.
10521313+15531313=2130+319565
44.
tan(αβ)
Answer.
62321+6232=3013619

Exercise Group.

Find the exact value of each expression given
51.
sin(α+β)
Answer.
3343478+53434158=2134+5510272
52.
cos(α+β)
Answer.
534347833434158=35343510272
53.
tan(α+β)
Answer.
35+157135157=480+11915545
54.
sin(αβ)
Answer.
334347853434158=21345510272
55.
cos(αβ)
Answer.
5343478+33434158=3534+3510272
56.
tan(αβ)
Answer.
351571+35157=48011915545

Exercise Group.

Find the exact of each expression given sinα=2029, 0<α<π2 and cosβ=2425, 0<β<π2

Exercise Group.

Find the exact of each expression given tanα=815, π<α<3π2 and cosβ=35, π2<β<π

Exercise Group.

Verify the identity.
77.
sin(θ+π2)=cosθ
78.
sin(θπ)=sinθ
79.
cos(θπ)=cosθ
80.
tan(θπ)=tanθ
81.
tan(π4θ)=1tanθ1+tanθ
82.
sin(π2θ)=sin(π2+θ)
83.
cos(θ+π3)=sin(xπ6)
84.
cos(x+y)cos(xy)=cos2xsin2y
85.
sin(x+y)cosxcosy=tanx+tany
86.
cot(xy)=cotxcoty+1cotycotx
87.
sin(x+y)sin(xy)=2cosxsiny
88.
cos(x+y)+cos(xy)=2cosxcosy

Exercise Group.

Write each expression in terms on sine only. Round your angles to one decimal.
89.
22sinx22cosx
Answer.
sin(x+225)
90.
32sinx12cosx
Answer.
sin(x+210)
92.
32sinx12cosx
Answer.
sin(x+210)
94.
5sinx9cosx
Answer.
106sin(x+240.9)
95.
8sinx2cosx
Answer.
68sin(x+346.0)
96.
7sinx+4cosx
Answer.
65sin(x+150.3)

97.

Use the Subtraction Formula for Cosine to prove the Cofunction Identity for Sine: sinθ=cos(π2θ).